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Norton’s Theorem: Simplifying Linear Circuits with Current Sources and Parallel Resistance

What is Norton’s Theorem?

Norton’s Theorem shows that any linear circuit—regardless of complexity—can be reduced to an equivalent circuit composed of a single current source in parallel with a resistance. The term “linear” carries the same meaning as in the Superposition Theorem: all relationships must be linear (no exponents or roots).

Simplifying Linear Circuits

Our starting circuit and its Norton equivalent look like this:

Norton’s Theorem: Simplifying Linear Circuits with Current Sources and Parallel Resistance

… after applying Norton conversion …

Norton’s Theorem: Simplifying Linear Circuits with Current Sources and Parallel Resistance

A current source delivers a fixed amount of current, providing whatever voltage is necessary to maintain that current.

Thevenin’s Theorem vs. Norton’s Theorem

Just like Thevenin’s Theorem, all elements except the load resistance are collapsed into a simpler form. The steps to compute the Norton source current (I_Norton) and Norton resistance (R_Norton) mirror those used for Thevenin’s equivalents.

Identify the Load Resistance

First, locate the load resistor and remove it from the original network:

Norton’s Theorem: Simplifying Linear Circuits with Current Sources and Parallel Resistance

Find the Norton Current

Next, short the two load terminals and calculate the resulting current. This step is the inverse of Thevenin’s approach, where the load is opened.

Norton’s Theorem: Simplifying Linear Circuits with Current Sources and Parallel Resistance

With zero voltage across the short, the current through R₁ equals the source voltage of B₁ divided by R₁: 7 A. Similarly, the current through R₃ equals the voltage of B₂ divided by R₃: 7 A. The total current through the short is 7 A + 7 A = 14 A, which becomes I_Norton in the equivalent model:

Norton’s Theorem: Simplifying Linear Circuits with Current Sources and Parallel Resistance

Find the Norton Resistance

To determine R_Norton, replace all independent voltage sources with short circuits and all independent current sources with opens, then measure the resistance between the two load terminals:

Norton’s Theorem: Simplifying Linear Circuits with Current Sources and Parallel Resistance

The Norton equivalent now appears as:

Norton’s Theorem: Simplifying Linear Circuits with Current Sources and Parallel Resistance

Compute Voltage Across the Load Resistor

Re‑attach the 2 Ω load and treat the Norton circuit as a simple parallel arrangement:

Norton’s Theorem: Simplifying Linear Circuits with Current Sources and Parallel Resistance

As with Thevenin’s model, the key outcome is the voltage and current across the load resistor. The Norton representation allows rapid re‑analysis for multiple load values using only basic parallel‑circuit formulas.

Review

Related Worksheet


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